Someone on Khan Academy said I could make a repeating function.
So now i must try.
//CAUSE I LOVE RAINBOWS, they are pretty. No real other reason.
var RAINBOW = (random(0,175 ), random(0, 75), random(0, 175));
strokeWeight(2);
stroke(RAINBOW);
//make lines!
var draw = function() {
background(223, 225, 237);
//trying to make a line repeat without typing code for each line
//I made a list for colors, but the OH NOES!!! guy keeps prompting me to use
//the blue() command, so apparently you can't use the word blue!!!
//i is for the plottinglist... or repeat function I plan on making
//empty plotting list, so you can make it whatever length you want
var plottinglist = [];
plottinglist.length = 40; //so here you could ask for user input.
for (var i = 0; i < plottinglist.length; i+=1) {
var x1 = 0;
var x2 = 400;
var y1 = 10;
var y2 = 10;
var change = i * 10;
line(x1, y1 + change, x2, y2 + change);}
for (var i = 0; i < plottinglist.length; i+=1) {
var change = i * 10;
var x = 10;
var y = 10;
var xa = 10;
var ya = 400;
line(x + change, y, xa + change, ya);}
};
So now i must try.
//CAUSE I LOVE RAINBOWS, they are pretty. No real other reason.
var RAINBOW = (random(0,175 ), random(0, 75), random(0, 175));
strokeWeight(2);
stroke(RAINBOW);
//make lines!
var draw = function() {
background(223, 225, 237);
//trying to make a line repeat without typing code for each line
//I made a list for colors, but the OH NOES!!! guy keeps prompting me to use
//the blue() command, so apparently you can't use the word blue!!!
//i is for the plottinglist... or repeat function I plan on making
//empty plotting list, so you can make it whatever length you want
var plottinglist = [];
plottinglist.length = 40; //so here you could ask for user input.
for (var i = 0; i < plottinglist.length; i+=1) {
var x1 = 0;
var x2 = 400;
var y1 = 10;
var y2 = 10;
var change = i * 10;
line(x1, y1 + change, x2, y2 + change);}
for (var i = 0; i < plottinglist.length; i+=1) {
var change = i * 10;
var x = 10;
var y = 10;
var xa = 10;
var ya = 400;
line(x + change, y, xa + change, ya);}
};
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